Question

Find the least number which when divided by 6, 15 and 18 leave remainders in each case​

Answer 1

Answer:

95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.

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Answer 2

$first \: find \: the \: lcm \: of \\ 16 \: \: 15 \: \: 18 \\ = 2 \times 3 \times 3 \times 5 \\ = 90 \\ therefore \: the \: required \: number \\ = 90 + 5 \\ = 95 \: answer$