Question

Find the least number which when divided by 6, 15 and 18 leaves remainder 5 in each case.​

Answer 1

$\huge{\underline{\mathtt{\blue{A}\red{N}\pink{S}\green{W}\purple{E}\orange{R}}}}$

Step-by-step explanation:

6 = 2 × 3

15 = 3 × 5

18 = 2 × 3 × 3

L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5

L.C.M (6, 15 and 18) = 90

Therefore, the required number = 90+5 = 95

As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.

As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.

Answer 2

Answer:

$\huge\star\underline{\orange{❥︎a}\mathfrak\blue{n}\mathfrak\purple{S}\mathbb\pink{wer}}\star\:$

95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.