If the system of equations 3x+y=1 and (2K-1)x+(K-1)y=(2K+1) is inconsistent, then K=
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Answer:
given
3x+y=1
(2k-1)x+(k-1)y=(2k+1)
a1=3,b1=1,c1=-1
a2=2k-1,b2=k-1,c2=-2k-1
=a1/a2=b1/b2=c1/c2
=3/2k-1=1/k-1=-1/2k-1
=3/2k-1=1/-2k-1
now by cross multiplying we get
3(-2k-1)=-1(-2k-1)
=-6k+3=-2k+1
-4k=-2
k=-4/-2
k=2
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