Math, asked by sallaruthvik, 10 months ago

If the system of equations 3x+y=1 and (2K-1)x+(K-1)y=(2K+1) is inconsistent, then K=

Answers

Answered by Sakshigupta15
11

Answer:

given

3x+y=1

(2k-1)x+(k-1)y=(2k+1)

a1=3,b1=1,c1=-1

a2=2k-1,b2=k-1,c2=-2k-1

=a1/a2=b1/b2=c1/c2

=3/2k-1=1/k-1=-1/2k-1

=3/2k-1=1/-2k-1

now by cross multiplying we get

3(-2k-1)=-1(-2k-1)

=-6k+3=-2k+1

-4k=-2

k=-4/-2

k=2

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