Find the least number which when divided by 6,15 and 18 give remainder 5 in each case
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Solution
L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90
Therefore the required number = 90+5=95
L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90
Therefore the required number = 90+5=95
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