Math, asked by tejasvi8787, 7 months ago

FIND THE LEAST NUMBER WHICH WHEN DIVIDED BY 6, 15 AND 21 LEAVES A REMAINDER 3 IN EACH CASE

Answers

Answered by aayushgid1729

7

Answer:

213

Step-by-step explanation:

you can find the answer by taking l.c.m. which is 210 of the three number and then add 3 so it becomes 213

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