Question

Find the least number which when divided by 615 and 18 leaves remainder 5 in each case

Answer 1

Given Numbers are 6, 15, and 18. Remainder left when divided is 5.

First we find the LCM of the given numbers,so prime factors of given number are

6=2*3

15=3*5

18=2*3*3

LCM (6,15,18)=2*3*3*5

=90, is the number exactly divisible by all 6, 15, and 18.

When 95 is divided by 90, remainder left is 5.

All given numbeers are greater than the remainder 5.

Hence,95 is the least number when divided by the given numbers ,leave a reminder of 5 in each case