Math, asked by ms9744771, 10 months ago

Find the least number which when divided by 7, 16, 22 leaves remainder 5 in each case​

Answers

Answered by rahulkumawat4040
0

Smallest five digit number = 10000

Let us divide this by the L.C.M of 7, 11, 21

L.C.M of 7, 11, 21 = 231 (Refer to calculate the LCM)

Dividing 10000 by 231 leaves a reminder 67 , Subtract 67 from 10000 = 9933

So this means 9933 is divisible by 231.

9933+231 = 10164 (which will also be divisible by 231, 7, 11 and 21)

To find the number which leaves reminder 5, we have to add 5 to 10164.

So the answer is 10169.

Answered by DynamicPlayer
4

Co-prime number is a set of numbers or integers which have only 1 as their common factor i.e. their highest common factor (HCF) will be 1.

Co-prime numbers are also known as relatively prime or mutually prime numbers.

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