find the least number which when divided by 8,10,16 and leave remainder 3 in each case?
Answers
Answered by
3
Step-by-step explanation:
Answer. These nos. are 51 ( 48×1 + 3), 99 (48×2 + 3), 147 ( 48×3 +3)... and so on. The least of them which leaves no remainder when divided by 7 is 147.
Answered by
2
Answer:
83
Step-by-step explanation:
8,10,16
remainder=3
LCM of 8,10,16 =80
required number = (LCM of 8, ,10,16 + remainder)
=80+3
= 83
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