Find the least number which when divided separately by15,20,36and 48leaves 3 as remainder in each case?
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number is L.C.M(15 , 20 , 36 , 48) + 3
15 = 3 * 5
20 = 2² * 5
36 = 2² * 3²
48 = 2 ^4 * 3
∴lcm (15 , 20 , 36 , 48) = 2 ^4 * 3 ^2 * 5 = 16 * 45 = 720
therefore number = 723
15 = 3 * 5
20 = 2² * 5
36 = 2² * 3²
48 = 2 ^4 * 3
∴lcm (15 , 20 , 36 , 48) = 2 ^4 * 3 ^2 * 5 = 16 * 45 = 720
therefore number = 723
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