Question

Find the least number which when divisible by 12 , 40 , 75 leaves remainder 5 in each case

Answer 1

$<b>$
$\underline{Step \: 1}$ :- We will find the LCM of 12, 40 and 75

12 = 2 × 2 × 3

40 = 5 × 2 × 2 × 2

75 = 5 × 5 × 3

LCM = 600


$\underline{Step \: 2}$ :- We will add 5 to the LCM, i.e, 600

600 + 5 = 605




$\therefore{}$ The least number is 605

Answer 2

Here is your solution

Firstly

We will find the LCM of 12, 40 and 75

12 = 2 × 2 × 3

40 = 5 × 2 × 2 × 2

75 = 5 × 5 × 3

LCM (12,40,75) = 600

Step2​ :- We will add 5 to the LCM, i.e, 600

600 + 5 = 605

∴ The least number is 605