Question

find the least number which when increased by 3 is divisible by 36 40 and 64​

Answer 1

To find the least number which when increased by 3 is divisible by 36 40 and 64 we have to find the LCM

Prime Factorisation of Numbers

$36 = 2 \times 2 \times 3 \times 3$

$40 = 2 \times 2 \times 2 \times 5$

$64 = 2 \times 2 \times 2 \times 2 \times 2 \times 2$

LCM OF 36,40,&64 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 5

2880 is the number which is already increased by 3.

So the required number is 2880—3 = 2877

2877 is the least number divisible by 36,40,64

Mark me as Brainlest......

Answer 2

Answer:

So, 2880 is the number which is already increased by 3. Hence, 2877 is the least number which when increased by 3 is divisible by 36, 40 and 64.