Find the least number which when is divided by 12 36 16 24 leaves a remainder 7 in each case
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1
Answer:
151
Step-by-step explanation:
The number we are looking for is LCM of listed numbers + 7
Let's find LCM of the given numbers.
12 = 2*2*3
16 = 2*2*2*2
24 = 2*2*2*3
36 = 2*2*3*3
LCM(12,16,24,36)=2*2*2*2*3*3= 144
And adding 7: 144+7=151
So 151 is the smallest number we found
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