find the least positive value ok k for which x² + kx + 16 = 0 has real roots
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Answered by
7
for real roots
b² - 4ac > 0
so k² - 64 > 0
if k² = 64 then k = 8
that is greater than 0
so k = 8
b² - 4ac > 0
so k² - 64 > 0
if k² = 64 then k = 8
that is greater than 0
so k = 8
Answered by
3
for real roots
b²-4ac>=0
k²-4*1*16>=0
k²-64>=0
k²>=64
k>=8
b²-4ac>=0
k²-4*1*16>=0
k²-64>=0
k²>=64
k>=8
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