Math, asked by Bhushan4592, 10 months ago

Find the least possible 5-digit number,which when divided by 10,12,16and 18 leaves remainder 27

Answers

Answered by Anm777
32

LCM of 10,12,16,18 = 720

Least 5-digit multiple of 720 = 10080

Adding 27 to this number .

10080+27 = 10107

The least possible number which when divided by 10,12,16 and 18 leaves remainder 27 is 10107 .

Answered by FelisFelis
19

The required number is 10107.

Step-by-step explanation:

Consider the provided information.

We need to find the least possible 5-digit number,which when divided by 10, 12, 16 and 18 leaves remainder 27.

First calculate the LCM of 10, 12, 16 and 18

10 = 2×5

12 = 2×2×3

16 = 2×2×2×2

18 = 2×3×3

Therefore, the LCM is: 2×2×2×2×3×3×5 = 720

Now we need to find a lest possible 5 digit number.

On dividing 10000 by 720 we get 640 as remainder.

Required number = 10000+(720-640)+27=10107

Hence, the required number is 10107.

#Learn more

If (K-8) is the highest common factor of 56 and 77 then what is the value of k

brainly.in/question/11558558

Similar questions