find the least smallest number which when divided by 6, 15 and 18 leave a reminder 5 in each case
Answers
Answered by
4
To find the required number we have to calculate LCM of 6, 15 and 18 because LCM is the least number divided by all 6, 15 and 18
LCM = 2 × 3 × 3 × 5 = 90
Since the number required always leaves remainder 5
Required number = 90+5 = 95
hope it helps pls mark as BRAINLIEST
Answered by
0
Step-by-step explanation:
- I hope this answers is useful for you
Attachments:
Similar questions