Question

Find the least square number which is exactly divisible
each of thenumber 8, 9, 10 and 15.​

Answer 1

Solution :

$\bigstar$ Firstly, we get L.C.M of each number 8,9,10 & 15 ;

$\begin{array}{r|l} 2 & 8,9,10,15 \\ \cline{2-2} 2 & 4,9,5,15 \\ \cline{2-2} 2 & 2,9,5,15 \\ \cline{2-2} 3& 1,9,5,15 \\ \cline{2-2} 3 & 1,3,5,5 \\ \cline{2-2} 5& 1,1,5,5 \\ \cline{2-2} & 1,1,1,1 \end{array}}$

Prime factorization = 2 × 2 × 2 × 3 × 3 × 5

We should multiply by 2 & 5 to get complete square number.

Thus;

⇒ The required square number = 2² × 2² × 3² × 5²

⇒ The required square number = 4 × 4 × 9 × 25

⇒ The required square number = 3600

Answer 2

Step-by-step explanation:

You answer is 3600

8=2*2*2

9=3*3

10=5*2

You number will be

you have to take the number of series

No. =2*2*2*3*3*5 There is one pair of 5 and 2 are missing so multiply it by10(5*2)

=8*9*5 *2*2=3600

Hope it helps.

Mark it brainlist.

Thanks

and also follow me to get best maths answers especially for class 9 and 10 .