Find the least value for n which 1 +3+32+...3power n-1>1000
Answers
Answered by
1
we know Sn=a(r^n-2) upon r-1
Sum of the given G.P. is
Sn=1 (3^n-1) upon 3-1
Now according to question, we have
1 (3^n-1) upon 3-1>2000
3^n +1-1>4000
3^n +1>4001
3^7<4001<3^8
Therefore, n=7
your answer is 7
Similar questions