find the least value of 3sinx – 4cosx + 7
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Answered by
5
Answer:
- maximum value is = (a2 + b2)
- while minimu value is = – (a2 + b2)
- maximum value is = (32 + 42) – 7 = 5 –7 = –2.
- minimum value is = – (32 + 42) – 7 = –5 – 7 = –12.
Answered by
2
Answer:
-12 is answer of question
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