Question

Find the least value of x and y so that the number 5 x 4 2 3 y is divisible by 88

Answer 1

Answer:

Step-by-step explanation:

Since x34,586,23y is divisible by 88=8*11 then it's divisible by both 8 and 11.

Now, in order a number to be divisible by 8 its last three digits must be divisible by 8, so 23y must be divisible by 8. That's only possibly if y=2 --> 232/8=29. So, our number is x34,586,232.

Next, in order a number to be divisible by 11 the difference between the sum of the odd numbered digits (1st, 3rd, 5th...) and the sum of the even numbered digits (2nd, 4th...) must be divisible by 11. So, (x+4+8+2+2)-(3+5+6+3)=x-1 must be divisible by 11, which means that x can only be 1.