Question

. Find the least value that k can take in x > 0) such that the square root of x' is a perfect cube​

Answer 1

Answer:

Step-by-step explanation:

Given : 72K=x  

3

 

Let us prime factorize 72 .

72=2×2×2×3×3..(i)

For a number to be a perfect cube , it must  have all the numbers in triplet.

Here , 3 is not in the form of triplet, hence we multiply (i) both the sides with 3.  

⇒72×3=2×2×2×3×3×3

⇒216=2×2×2×3×3×3

Now 2 and 3 are in triplets.

⇒72K=216

⇒K=  

72

216

​  

 

⇒K=3

The value of K is 3

Answer 2

Step-by-step explanation:

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