Question

Find the leastvpisitive value of k for whicjbx2+kx+16=0

Answer 1

❤2+kx+16=0
2+kx=-16
kx=-16-2
kx=-18
k=-18/x

Answer 2

Question:

Find the least positive value of k for which the x2+Kx+16=0 has real roots.

Answer:

Given equation, 

x² + kx + 16 = 0

According to, 

D = B² - 4AC 

k² - 4 × 1 × 16 

k² = 64 

If D > 0 , it will have real roots. 

D > 0 => K² - 64 > 0

k² > 64 

k > +8 or -8 !!

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