Question

Identify the oxidant and reductant in the following reaction: $I_{2}(g)+H_{2}S(g) \longrightarrow 2HI(g)+S(s)$

Answer 1

Hey friend....

Here is your answer...

The oxidant or oxidising agent is:
▪️H2S
The reductant or reducing agent is :
▪️I2


Hope this helps you

Answer 2

"${ I }_{ 2 }(g)\quad +\quad { H }_{ 2 }S(g)\quad \rightarrow \quad 2HI(g)\quad +\quad S(s)$

In the above reaction, the sulphur is the reductant and iodine is the oxidant

Sulphur:  From -2 oxidation state sulphur is changed to 0 oxidation state

Iodine: From 0 oxidation state iodine is changed to -1 oxidation state

The "oxidizing agent" is an "electron acceptor" and "reducing agent" is an "electron donor"."