Question

Find the length and breadth of a rectangle whose length is 4m more than four times its breadth and its
perimeter is 60m.

Answer 1

Answer:

Lenght= 4+4x

Breadth= x

2(4+4x+x)= 60

2(4+5x)=60

8+5x=60

5x=60-8

5x=52

x=52/5

x= 10.4

so breadth is 10.4

lenght= 10.4×4+4= 45.6

Lenght= 45.6m Breadth= 10.4m

Answer 2

Answer:

Therefore, l = 17 m and w = 13 m are indeed the length and width, respectively, of the given rectangle.

Step-by-step explanation:

Let l = the length of the given rectangle, and let w = the width of the given rectangle.

Since the length l of the given rectangle is 4 m more than the width, then l = w + 4 m.

The formula for the perimeter P of a rectangle is: P = 2l + 2w. We're given that the perimeter of the given rectangle is 60 m.

Now, substituting into the perimeter formula for P and l, we get:

P = 2l + 2w

60 m = 2(w + 4 m) + 2w

60 m = 2w + 2(4 m) + 2w

60 m = 2w + 8 m + 2w

60 m = 2w + 2w + 8 m

60 m = 4w + 8 m

60 m - 8 m = 4w + 8 m - 8 m

52 m = 4w + 0

4w = 52 m

(4w)/4 = (52 m)/4

(4/4)w = (52 m)/4

(1)w = 13 m

w = 13 m

Therefore, l = w + 4 m

l = 13 m + 4 m

l = 17 m

CHECK:

P = 2l + 2w

60 m = 2(17 m) + 2(13 m)

60 m = 34 m + 26 m

60 m = 60 m