Find the length and perimeter of a rectangle if its breadth and area are 19 m and 475 m2
Answers
Answered by
11
Let us assume that the length of rectangle is x
as we know that
area of rectangle=length×breadth
475=19×x
x=475/19
x=25
length of rectangle is 25cm
perimeter of rectangle=2×(lenght+breadth)
=2×(25+19)
=2×44
=88
perimeter of rectangle is 88cm
as we know that
area of rectangle=length×breadth
475=19×x
x=475/19
x=25
length of rectangle is 25cm
perimeter of rectangle=2×(lenght+breadth)
=2×(25+19)
=2×44
=88
perimeter of rectangle is 88cm
Answered by
2
Answer:
Length=25 m , Perimeter=88 m
Step-by-step explanation:
Given : Area=475 m^2 , Breadth = 19 m
To find: Length , Breadth
soln
so,X=length,( for now only)
A of Rectangle = 475 sq. m
475 =19 × X
X = 475/19
X = 25
So,length=25 m
P = 2 x (l x b)
=2 x (25 x 19)
=88 m
Perimeter = 88 m
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