Math, asked by st275214, 11 months ago

find the length of 10 metre wide room whose perimeter is 44 m​

Answers

Answered by dhanyachethala
2

Answer:


Step-by-step explanation:

B=10m

P=44m

P=2 (l+b)

2(l+10)=44

l+10=44%2=22

L= 22-10

L=12m


st275214: thanks
Answered by samuelpaul
5

Answer:12


Step-by-step explanation:

We know that, perimeter of a room=2(Length{L}+Breadth{B})

Given perimeter=44m;Breadth B=10m

from formula,Substitute the values in it..

44=2(L+B) [∵2 goes to LHS from multiplication to division]

44÷2=(L+10)

22=L+10[∵+10 goes to LHS and becomes -10]

22-10=L

12=L

Hence,The value of Length is 12

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Thank you!



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