find the length of a chord a b in which at a distance of 6 cm from the centre of a circle having radius 10 cm
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Answer:
16cm
Step-by-step explanation:
given radius:10cm
given perpendicular distance from the centre to the chord:6cm
join the two ends of the chord from the centre i.e.join oa and ob.
two right angled triangles are formed.
apply Pythagoras theorem to each triangle and find the base of the triangles
each base of triangle:
√10^2-6^2
√100-36
√64
8cm
then the triangles' bases are 8+8 cm
=16cm
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