Question

find the length of a chord which is 6cm away from the centre of a circle of radius 10cm

Answer 1

According to theorem the perpendicular drawn from the centre of a circle to a chord bisects the chord
By applying pythagoras theorem
half length of chord=8cm
Total length=2*8=16 cm

Answer 2

$\sqrt{ {10}^{2} - {6}^{2} } = \sqrt{100 - 36} = \sqrt{64} = 8cm$

$length \: of \: the \: chord = 2 \times 8 = 16cm$