The far point of a myopic person is is 80cm in front of the eye.. What is the nature and power of the lens required to correct the defect ?
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Answered by
13
We used concave lens to correct it.
U = infinity
V=-80 cm
1/f=1/v-1/u
1/f=-1/80
F=-80cm
=0.8 m
Now power
P=1/f =1/-0.8 =-1. 25
Hope it will help you well friend
U = infinity
V=-80 cm
1/f=1/v-1/u
1/f=-1/80
F=-80cm
=0.8 m
Now power
P=1/f =1/-0.8 =-1. 25
Hope it will help you well friend
Answered by
1
Explanation:
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