find the length of a chord which is at a distance of 12cm from the centre of the circle of radius 13 CM.
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Answered by
1
By Pythagoras theorem,
(Radius)² =(distance)²+(half of chord)²
13² = 12²+(half of chord)²
169=144+(half of chord)²
169-144= (half of chord)²
25=(half of chord)²
√25=5cm = (chord/2)
5*2 =chord
10 cm =chord
Lenght of chord is 10cm
I hope this will help you
-by ABHAY
(Radius)² =(distance)²+(half of chord)²
13² = 12²+(half of chord)²
169=144+(half of chord)²
169-144= (half of chord)²
25=(half of chord)²
√25=5cm = (chord/2)
5*2 =chord
10 cm =chord
Lenght of chord is 10cm
I hope this will help you
-by ABHAY
Answered by
3
Radius of circle = 13 cm
Distance of chord from the Centre = 12 cm
By Pythagoras theoram,
In Triangle AOP
AP = sqrt ( 13^2 - 12^2)
AP = sqrt ( 169 - 144)
AP = sqrt 25
AP = 5 cm
Length of chord = 2 × AP
= 2 × 5
= 10 cm
Distance of chord from the Centre = 12 cm
By Pythagoras theoram,
In Triangle AOP
AP = sqrt ( 13^2 - 12^2)
AP = sqrt ( 169 - 144)
AP = sqrt 25
AP = 5 cm
Length of chord = 2 × AP
= 2 × 5
= 10 cm
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