Question

find the length of a chord which is at a distance of 2√11 cm from the centre of a circle of the radius 12 cm​

Answer 1

Step-by-step explanation:

Let centre be O and chord be AB

Distance(OC)=2√11cm

Radius(OA)=12cm

so in triangle OAC,

OA²=OC²+AC²

144=44+AC²

AC²=100

AC=10

AC is half of AB

so AB = 20 cm

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Answer 2

Let center be O and chord be AB

Distance(OC)=2√11cm

Radius(OA)=12cm

so in triangle OAC,

OA²=OC²+AC²

144=44+AC²

AC²=100

AC=10

AC is half of AB

so AB = 20 cm