find the length of a chord which is at a distance of 4 cm from the centre of a circle of radius of 5 cm
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Answer:
6 cm
Step-by-step explanation:
in this OA is radius and OC is distance between chord
by Pythagoras theorem,
5²=4²+x²
X=3cm
the line which passing through centre tough chord at a point that line is perpendicular bisector
so ......AC=BC
AB=6cm
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