Find the length of a cord which is 3 cm distance from the centre of the circle with radius 5 cm
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It is the diagram.
Tr. AXO=~Tr. BXO by
RHS congruence condition as
OA=OB
OX perpendicular toAB
(line between centre and chord is perpendicular to the chord)
By CPCT,
AX=AB
=>2AX=AB
AX=Square root of (5sq.+3sq.)
[By pythagoras theorm]
=>AX=4cm
=>ChordAB = 8cm.
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Tr. AXO=~Tr. BXO by
RHS congruence condition as
OA=OB
OX perpendicular toAB
(line between centre and chord is perpendicular to the chord)
By CPCT,
AX=AB
=>2AX=AB
AX=Square root of (5sq.+3sq.)
[By pythagoras theorm]
=>AX=4cm
=>ChordAB = 8cm.
If you like my answer
Please mark it as brainliest
And
Be my follower if possible.
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