Find the length of a factangle whose breadth 12.5 cm
and perimeter is 80 cm
Answers
Answered by
2
Step-by-step explanation:
primeter of rectangle=2(L+B)
2(L+B) 80=2(L+12.5)
2(L+B) 80=2(L+12.5) 80=2L+ 25
2(L+B) 80=2(L+12.5) 80=2L+ 25 80-25=2L
2(L+B) 80=2(L+12.5) 80=2L+ 25 80-25=2L 55/2= L
27.5 = L
Answered by
0
Answer:
Length l of Rectangle =12.5m
Breadth b of Rectangle =8dm=0.8m
Area of rectangle = length×breadth
= l×b
=12.5×0.8
= 10m
2
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