Find the length of a ladder kept at a distance of 16m from the foot of a wall that reaches a window at a height of 30m .
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Answered by
18
Height Of triangle(Wall) = 30 m
Base Of Triangle(Distance) = 16 m
Hypotenuses of triangle(length of ladder) = L
using Pythagoras theorem,
L^2=B^2+H^2
L^2=(16)^2 + (30)^2
L^2=(256 + 900) = 1156 m^2 =(34)^2
hence length of ladder is 34 m...
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Base Of Triangle(Distance) = 16 m
Hypotenuses of triangle(length of ladder) = L
using Pythagoras theorem,
L^2=B^2+H^2
L^2=(16)^2 + (30)^2
L^2=(256 + 900) = 1156 m^2 =(34)^2
hence length of ladder is 34 m...
hope it is helpfull..
mark as best...
thanku..
have a nice day dear...
Answered by
9
Given,
height of the wall that reaches the window(AB)=30m
distance b/w the foot of the ladder and the building(BC)=16m
length of the ladder(AC)=?
by pythagorous theorem,
AC*2=AB*2+BC*2
AC*2=30*2+16*2
=900+256
=1156
So,AC=34
so,the length of he ladder is 34m...............................................hope it helped you
height of the wall that reaches the window(AB)=30m
distance b/w the foot of the ladder and the building(BC)=16m
length of the ladder(AC)=?
by pythagorous theorem,
AC*2=AB*2+BC*2
AC*2=30*2+16*2
=900+256
=1156
So,AC=34
so,the length of he ladder is 34m...............................................hope it helped you
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