Question

Find the length of a rectangle given that its perimeter is 880 m and breadth is 88 m.

Answer 1

Answer:

perimeter of rectangle =2*(l+b)

let length =l m,

given breadth =88m,

perimeter =880m,

therefore,2(l+b)=880;

2(l+88)=880;

l+88=440;

l=352m

Ans :- Length=352

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Answer 2

✬ Length = 352 m ✬

Step-by-step explanation:

Given:

• Perimeter of rectangle is 880 m.
• Meaure of breadth of rectangle is 88 m.

To Find:

• What is the meaure of length of rectangle ?

Solution: Let the meaure of length of rectangle be l cm.

As we know that

★Perimeter of Rectangle =2(Length + Breadth)★

A/q

• Perimeter = 880 m

$\implies{\rm }$ 880 = 2( l + b )

$\implies{\rm }$ 880 = 2( l + 88 )

$\implies{\rm }$ 880 = 2l + 176

$\implies{\rm }$ 880 – 176 = 2l

$\implies{\rm }$ 704 = 2l

$\implies{\rm }$ 704/2 = l

$\implies{\rm }$ 352 = l

Hence, the meaure of length of rectangle is l = 352 m

_____________

★ Verification ★

➟ 2( Length + Breadth ) = 880

➟ 2( 352 + 88 ) = 880

➟ 2 (440) = 880

➟ 880 = 880

$\large\boxed{\texttt{Verified}}$