Prove
that
sec0 + tan 0-1 =cos 0
tan 0- sec 0+1= 1-sin 0
Answers
Answered by
1
Step-by-step explanation:
sec 0=1 also cos 0 =1
tan 0=0 also sin 0=0
therefore
sec 0+tan 0-1=1+0-1=0=cos 0
tan0-sec 0+1=0-1+1=0=1-sin 0=1-1=0
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