Question

Find the length of a rectangle whose perimeter is 26 cm and the width is 4 upon 2 by 3

Answer 1

Answer:

$\huge\sf8=Breadth$

Step-by-step explanation:

As we know that -

Perimeter of Rectangle=$\large{\boxed{\sf2(L+B)}}$

Given:

Breadth or width is $\sf3\frac{4}{2}$

So,

According to question -

perimeter = 2(L+B)

26= $\sf 2(L+\frac{10}{2})$

26= $\sf2L +10$

26-10= $\sf2L$

= $\sf L=\frac{16}{2}$

= $\sf L=8$

${\boxed{\sf Verification:-}}$

=$\sf26=2(L+B)$

26 = (8+ 3+4/2)2

26 = (16+10)2

26 = 26