find the length of altitude and median of an equilateral triangle of length 12 cm using Pythagoras theorem
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Given:- Side of Equilateral Triangle = 12 cm
Let's Solve:- We know that Altitude of a triangle is perpendicular on side of triangle.
so, In ΔABD right angled at D
AD² = AB² - BD²
AD² = 12² - 6²
AD² = 144 - 36
AD = √108
AD = 6√3 cm
∴ Altitude of equilateral triangle = 6√3 cm
We know that Median of any triangle bisects the side on which it lies.
so, In ΔABD
AD² = AB² - BD²
AD² = 12² - 6²
AD² = 144 - 36
AD = √108
AD = 6√3 cm
∴ Median of equilateral triangle = 6√3 cm
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Anonymous:
Perfect ! :D
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