Find the length of angular bisector through B vertex . If AB=5CM ,BC= 5CM and AC=6CM
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or,(a²+b²+c²-3abc)-x=(2a²-b²-3c²+abc)
or,(a²+b²+c²-3abc)-(2a²-b²-3c²+abc)=x
or,a²+b²+c²-3abc-2a²+b²+3c²-abc=x
or,x=-a²+2b²+4c²-4abc
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By Angle bisector theorem: which states that, the ratio of any 2 sides of a triangle is equal to the ratio of the lengths of the segments formed on its third side, by the angle bisector of the angle formed by those 2 sides.
So, here, AB/AC = BD/DC
=> 6/5 = 3 / DC
=> DC = 15/6 = 5/2 = 2.5 cm
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