Question

Find the length of base in a right triangle where the length of the hypotenuse is 29 units and the length of perpendicular is 21 units.​

Answer 1

Answer:

base is 25

Try to do by yourself. It's so easy

Answer 2

Given data: In a right triangle, the length of the hypotenuse is 29 units and the length of perpendicular is 21 units.

To Find: The length of a base in right triangle.

Solution:

According to pythagoras theorem, in a right triangle,

$(Hypotenuse)^{2}=(Perpendicular)^{2}+(Base)^{2}$

Substitute, length of hypotenuse = 29 units, length of perpendicular = 21 units.

$29^{2}=21^{2}+(base)^{2}$

Transpose $21^{2}$ to left,

$29^{2}-21^{2}=(base)^{2}$

$841-441=(base)^{2}$

⇒$(base)^{2}=400$

Take square root on both sides,

$\sqrt{base^{2} } =\sqrt{400}$

$base=\sqrt{400}$

$base=20 units$

Therefore, the length of base in a right triangle is 20 units.