find the length of chord of a circle of radius 6cm,making an angle 60°at the centre
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FIND THE LENGTH OF CHORD OF A CIRCLE OF RADIUS 6CM,MAKING AN ANGLE 60°AT THE CENTREFIND THE LENGTH OF CHORD OF A CIRCLE OF RADIUS 6CM,MAKING AN ANGLE 60°AT THE CENTREFIND THE LENGTH OF CHORD OF A CIRCLE OF RADIUS 6CM,MAKING AN ANGLE 60°AT THE CENTREFIND THE LENGTH OF CHORD OF A CIRCLE OF RADIUS 6CM,MAKING AN ANGLE 60°AT THE CENTRE NIKKI1231 EXPERT GIVEN, RADIUS OF THE CIRCLE=6CM ANGLE MADE BY THE CHORD AT THE CENTER=60° LET THE OTHER ANGLES IN THE TRIANGLE BE X BECAUSE THE RADII OF THE CIRCLE ARE EQUAL WE KNOW THAT, SUM OF THE ANGLES IN THE TRIANGLE=180° =>X+X+60°=180° =>2X+60°=180° =>2X=120° =>X=60° SUCH THAT GIVEN TRIANGLE IS EQUILATERAL TRIANGLE. HENCE, IN THE EQUILATERAL TRIANGLE ALL SIDES ARE EQUAL. CHORD OF THE CIRCLE IS 6 CM HOPE U CAN UNDERSTAND PLS MARK IT AS BRAINLIEST .
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AO= OR ( radii)
As AO = OR .. angle OAR = angle ORA ..
consider triangle AOR ..
THE Sum OF ANGLES MUST BE 180°
SO.. 60° + angle OAR + angle ORA = 180°
2 angle OAR = 120 ( AS angle ORA = angle OAR)
therefore ... angle OAR = angle ORA = 60...
which implies triangle AOR is an equilateral triangle......
so AO=OR= AR
therefore the length of chord = radius of the circle
..
SO ... LENGTH OF CHORD = 6cm
As AO = OR .. angle OAR = angle ORA ..
consider triangle AOR ..
THE Sum OF ANGLES MUST BE 180°
SO.. 60° + angle OAR + angle ORA = 180°
2 angle OAR = 120 ( AS angle ORA = angle OAR)
therefore ... angle OAR = angle ORA = 60...
which implies triangle AOR is an equilateral triangle......
so AO=OR= AR
therefore the length of chord = radius of the circle
..
SO ... LENGTH OF CHORD = 6cm
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