find the length of chords AB
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Answered by
1
Answer:
8 cm
Step-by-step explanation:
In ∆OLB ,
OB = 5,OL=3
5 square = 3square + LB square
25 = 9 + LB square
25- 9 =16
LB = √16 = 4
chord AB = 2 × LB
AB = 2×4=8
Answered by
0
Answer:
8cm is the measure of chord
0B^2=OL^2+ LB^2
5^2=3^2+LB^2
25=9+LB^2
25-9=LB^2
√16=LB
4=LB
AB=2×LB
AB=2×4
AB=8cm
the measure of chord is 8cm
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