Question

find the length of diagonal of a rhombus whose area is 96CM^2 and other diagonal is 18 cm

Answer 1

Areaof Rhombus = 1/2 ×d1×d2 =96

d1 = diagonal & d2= diagonal

d2 = (96 ×2 )/d1

d2=( 96 ×2)/ 18

d2= 48/18= 8/3



So other diagonal is 8/3= 2.66cm

Answer 2

Area of Rhombus=0.5x Diagonal1 x Diagonal2, Therefore 96=0.5x18xX, Therefore X=10.667 CM