find the length of diagonal of a rhombus whose area is 96CM^2 and other diagonal is 18 cm
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Areaof Rhombus = 1/2 ×d1×d2 =96
d1 = diagonal & d2= diagonal
d2 = (96 ×2 )/d1
d2=( 96 ×2)/ 18
d2= 48/18= 8/3
So other diagonal is 8/3= 2.66cm
d1 = diagonal & d2= diagonal
d2 = (96 ×2 )/d1
d2=( 96 ×2)/ 18
d2= 48/18= 8/3
So other diagonal is 8/3= 2.66cm
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Area of Rhombus=0.5x Diagonal1 x Diagonal2, Therefore 96=0.5x18xX, Therefore X=10.667 CM
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