The diameter of the base of metallic cone is 2cm and height 10cm. 900 such cones are molten to form 1 right circular cylinder whose radius is 10cm. Find total surface area of the right circular cylinder so formed. ( Given π =3.14)
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Volume of cylinder = 1/3 ×π×r^2×h r= d/2=1cm
V=1/3 ×π×1× 10 =10π/3
volume of 900 cones = 900× 10π/3= 3000π
Volume of cylinder formed= 3000π
πr^2h = 3000π. *(r= 10cm)*
h=3000/r^2
h= 3000/ 10×10
h= 30 cm
Total Surface area of cylinder = 2πrh + 2πr^2
TSA= 2πr(r+h)= 2×3.14×10 (10+30)
============ 2512 sq cm
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V=1/3 ×π×1× 10 =10π/3
volume of 900 cones = 900× 10π/3= 3000π
Volume of cylinder formed= 3000π
πr^2h = 3000π. *(r= 10cm)*
h=3000/r^2
h= 3000/ 10×10
h= 30 cm
Total Surface area of cylinder = 2πrh + 2πr^2
TSA= 2πr(r+h)= 2×3.14×10 (10+30)
============ 2512 sq cm
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prithviraj2510p4lrr1:
You have written volume of cylinder but used formula of volume of cones..in the first step..plz do make the correction..at the latest..
It is my Mistake. I wrote cylinder in place of cone.
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