find the length of diagonal of rectangle with dimensions 20mby 15m(using Pythagorean triplet)
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▶️ In triangle BDC
=> BD = ?
=> BC = 5
=> DC = 12
⏺️ According to figure , it is very clear Pythagoras will be used
=> ( BD )^2 = ( BC )^2 + ( DC )^2
=> ( BD )^2 = 5^2 + 12^2
=> ( BD )^2 = 25 + 144
=> ( BD )^2 = 169
=> BD = √ 169
=> BD = 13
HOPE HELPED
HAVE A NICE DAY..
:-)
HERE IS UR ANSWER
____________________
▶️ In triangle BDC
=> BD = ?
=> BC = 5
=> DC = 12
⏺️ According to figure , it is very clear Pythagoras will be used
=> ( BD )^2 = ( BC )^2 + ( DC )^2
=> ( BD )^2 = 5^2 + 12^2
=> ( BD )^2 = 25 + 144
=> ( BD )^2 = 169
=> BD = √ 169
=> BD = 13
HOPE HELPED
HAVE A NICE DAY..
:-)
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ramcharan333:
buddy it was 15 not 5
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