Question

Find the length of each side of square whose area is equal to the area of rectangle of land 13.6 meter and bread three point for meter​

Answer 1

$\sf\large\underline{Correct\: Question:}$

Find the length of each side of square whose area is equal to the area of rectangle of length 13.6m and breadth 3.4m.

$\sf\large\underline{Given:}$

• $\rm{Length\:_{(rectangle)}=13.6m}$
• $\rm{Breadth\:_{(rectangle)}=3.4m}$
• $\rm{Area\:_{(rectangle)}=Area\:_{(square)}}$

$\sf\large\underline{To\: Find:}$

• $\rm{Side\:_{square}=?}$

$\sf\large\underline{Solution:}$

• At first calculate the area of rectangle than calculate the side of square here,]

$\rm{\implies Area\:_{(rectangle)}=Length\times\: Breadth}$

$\rm{\implies Area\:_{(rectangle)}=13.6\times\:3.4}$

$\rm{\implies Area\:_{(rectangle)}=46.24\:m^2}$

• Now calculate the side of square here]

$\rm{\implies Area\:_{(square)}=Area\:_{(rectangle)}}$

$\rm{\implies Area\:_{(square)}=S^2}$

$\rm{\implies S^2=46.24}$

$\rm{\implies S=\sqrt{46.24}}$

$\rm{\implies S=6.8m}$

$\sf\large{Hence,}$

$\rm{\implies Side\:_{(square)}=6.8m}$

$\sf\large\underline{Some\: related\: formula:}$

$\tt{\implies Perimeter\:_{(rectangle)}=2(Length+Breadth)}$

$\tt{\implies Perimeter\:_{(square)}=4\times\:side}$

$\tt{\implies Diagonal\:_{(square)}=\sqrt{2}\:a}$

$\tt{\implies Diagonal\:_{(rectangle)}=\sqrt{P^2+b^2}}$