find the length of hypotenuse of ABC if AB = 12 <B 90° and BC = 5cm
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(hypotenuse )sq. = (12)^2+5^2
(hypotenuse)^2 = 144+25
(hypotenuse)^2 = 169
hypotenuse = 13cm
(hypotenuse)^2 = 144+25
(hypotenuse)^2 = 169
hypotenuse = 13cm
Answered by
0
B=90°
So,
AC^2=AB^2 +BC^2
AC^2=(12)^2+(5)^2
AC^2=144+25
AC^2=169
AC=13cm
So,
AC^2=AB^2 +BC^2
AC^2=(12)^2+(5)^2
AC^2=144+25
AC^2=169
AC=13cm
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