Question

Find the length of Hypotonues if base is 4 m and perpendicular is 6 m​

Answer 1

Answer:

The length of Hypotonuous is

The length of Hypostoneus is

${h}^{2} = {b}^{2} + {p}^{2} \: \\ = {4}^{2} + {6}^{2} \\ 16 + 36 \\ {h}^{2} = 52 \\ h = \sqrt{52} m$

Answer 2

base is 4 m,

and perpendicular is 6 m

${h}^{2} = {b}^{2} + {p}^{2} \\ \\ {h}^{2} = {4}^{2} + {6}^{2} \\ \\ {h}^{2} = 16 + 36 \\ \\ {h}^{2} = 52 \\ \\ h = \sqrt{52} \: m \:$

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