Two blocks of masses 10 kg and 9 kg are connected with light string which is passing over an ideal pulley as shown in the figure. If system is released from rest, then the acceleration of the 9 kg block in the given instant is about (assume all surfaces are smooth and g= 10 m/s^2)
1) 1.8 m/s^2
2) 4.2 m/s^2
3) 3.5m/s^2
4) 3m/s^2
Answers
The acceleration of the block is a = 4.2 m/s^2
Explanation:
N.cos θ= mg.sinθ
N = mg.tanθ
N = 100 / √3 N ---- (1)
N.sinθ - mg.sinθ + T = 10a
100 /√3 x 1/2 - 100 x √3 /2 + 90 - 9a = 10a
100 /2√3 - 100 √3 / 2 + 90 = 19 a
200 - 600 / 4 √3 + 90 = 19.a
- 100 / √3 + 90 = 19.a
a ~ 1.8 m/s^2
N.sinθ = mg.sinθ
N = 100
N.cosθ - mg.cosθ + T = 10.a
100 x √3 / 2 - 100 x √3/2 + 90 - 9.a = 10.a
19.a = 90
a = 4.2 m/s^2
Thus the acceleration of the block is a = 4.2 m/s^2
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Explanation:
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