Question

Find the length of longest rod that can be placed in a room of dimensions 30 x 24 x18

Answer 1

Answer:

$diagonal \: of \: a \: cuboid \: = \: \sqrt{(l {}^{2} + b {}^{2} + h {}^{2} ) }$

$d = \sqrt{(30 {}^{2} + 24 {}^{2} + 18 {}^{2}) }$

$d = \sqrt{900 + 576 + 324}$

$d = \sqrt{1800}$

$d = 42.42 \: (approx)$

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